2+2=5

[kresola]

koristeći zakone matematike uspješno je dokazano da 2+2 može biti 5, nisam siguran, ali mislim da se može dokazat i za bilo koji broj... znači 2+2=bilo koji broj...

probajte vidit i skužit ako ima pogrešaka:

(1) let x = 2+2

(2)[multiply by x-1] x(x-1)=(2+2)(x-1)

(3) x^2 -x = 2x+2x-2-2

(4)[subtract 3x] x^2-4x=x-4

(5)[multiply by x-5] (x-5)(x^2-4x)=(x-5)(x-4)

(6)x^3-9x^2+20x=x^2-9x+20

(7)x(x-4)(x-5)=(x-4)(x-5)

(8)[divide by x-4] x^2-5x=x-5

(9)[add 4x] x^2-x=5x-5

(10)x(x-1)=5(x-1)

(11)[divide by (x-1)] x=5

And we started with x=2+2, therefore 2+2=5

[xarfaxus]

koliko san skuzija
ako je x=2+2
u jednon koraku kaze "divide by x-4''
znaci podjeli sa 4-4

[kresola]

"While a fun example of using simple mathematic properties to prove a falsehood it also point out why dividing by zero is undefined. But you don't see a divide by zero set I hear you say....well let uncle XXXXX show it to you.

In step one we set out that x=2+2 which we can rewrite as (x-(2+2))=0 by subtracting (2+2) from both sides of the equality. In step eight of the proof you'll see that we divide both side of the equation by (x-4) which we can rewrite as (x-(2+2)) since we have shown that (x-(2+2))=0 we are saying divide both sides of the equation by zero which is of course undefined. Still good fun."

Je, to je to...

NEMEREŠ DJELIT S NULOM!!!

[Servant]

[xarfaxus]

uu kako san dobar...olol da je to znanje iskoristit na ispitu

[Adolon]

Ima da izjebem sutra doktora matematike na faksu s ovim

[Medeny]

joj, kak je profesorica blejala pol ure dok je nisam prosvjetlila nije mogla skužit kaj je greška

[spaljevina]

Pravi autor: kresola

"While a fun example of using simple mathematic properties to prove a falsehood it also point out why dividing by zero is undefined. But you don't see a divide by zero set I hear you say....well let uncle XXXXX show it to you.

In step one we set out that x=2+2 which we can rewrite as (x-(2+2))=0 by subtracting (2+2) from both sides of the equality. In step eight of the proof you'll see that we divide both side of the equation by (x-4) which we can rewrite as (x-(2+2)) since we have shown that (x-(2+2))=0 we are saying divide both sides of the equation by zero which is of course undefined. Still good fun."

Je, to je to...

NEMEREŠ DJELIT S NULOM!!!

mozes

x/0=beskonacno

[werner]

x/0 nije beskonačno, nego nema rešenja u skupu realnih brojeva.
Druga stvar: x/y jeste beskonačno, ako y TEŽI nuli, tj. granična vrednost ovog izraza je tada beskonačno.

[spaljevina]

to znam........
ali logički gledano x/0 je beskonacno.......jer..........kad bi recimo podijelio neki broj na nula dijelova........onda bi nekom logikom dobio beskonacno mnogo tih dijelova.......kuzis.......kad neki broj tezi nuli to zapravo nije beskonacno nego jako veliki veliki broj....pa se kaze da tezi beskonacnom......a x/0 nema rijesenja jer beskonacan broj ne postoji pa ze zato kaze da nema rijesenja